Question

A 5 kg block drops 2m upon a spring whose modulus is 10000 N/m. What will be the speed of the block when the spring is deformed 0.1m.

Answer 1

Answer:

bjxhxhxhxb

Explanation:

bxbdnnxdnndnxnxnbbbb h

Answer 2

Given,

Mass of the block=5kg

Spring modulus=10000N/m

Deforming distance=0.1m

To Find,

Speed of the block.

Solution,

We can find out the speed by using conservation of energy equation.

By using it,

Pi+Pf=Ki+Kf

mgh = (0.5)kx^2 + (0.5)mv^2 (∵Initial there will be no height so initial potential is 0 at that point)

⇒5(10)(2) = 0.5(10000)(10^-2) + (0.5)(5)(v^2)

⇒100 = 50 + (2.5)(v^2)

⇒v^2 = 20

⇒v = 2√5 m/s

Hence, the speed of the block will be 2√5m/s.