a 5 kg block is placed on 3 kg block b which is at rest on the table coefficient of the friction between a and b is 0.3 and between b and table is 0.4 a 40 newton horizontal force is applied on the table b then the friction force between the block a and b is
(1) Zero (2) 15N
(3) 60N (4) 45N
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F=mew suffix r*N use it,,,
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