Question

a 5 kg box on a horizontal table is pushed by a horizontal force of 15N value of coefficient of friction=0.4. The value of normal force is

Answer 1

Answer:

Given data are

mass of the box, m=15N

Applied force, F=15N

Coefficient of friction, μs=0.4

Frictional force flim=μsN=μmg=0.4×15×9.8=19.6N

Since the frictional force is greater than the applied force, therefore it must be limiting friction. In this case, the block is still at rest.

Explanation:

here your answer please mark me as brainlist