Question

A 5 Kg gun fires a bullet of 15 grams at a velocity of 1000 m/s to the right. What is the velocity of recoil of the gun?

Answer 1

Answer:

Explanation

We know that momentum is conserved according to law of conservation of momentum

Hence

Momentum of gun (recoil)=Momentum of bullet

5kg*recoil velocity=15kg/1000*1000m/s

Recoil velocity is 3m/s

Answer 2

Answer:

3 m/s

Explanation:

Take right to be positive.

By conservation of momentum,

momentum of bullet + momentum of gun = 0 kg m/s (originally nothing is moving)

(.015)(1000) + (5)(v) = 0

v = -15/5

v = -3 m/s

Therefore, velocity of recoil of the gun is 3 m/s.