A 5 kg hammer fall with a velocity 1 m/s on a piece of lead of mass 300 g at 27 degreecelcius how many strokes will be required for melting the lead
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given m=5kg v=1m/s
L(Heat of fusion)=25200 J/kg
C((Specific heat)=125J/kg ,
∆T(C in temp) =327-27=300K
n(number of strokes) =?
n(1/2)5×1^2=mcΔT+mL
n(1/2)×5×1^2=m(cΔT+L)
=0.3kg(125×300+25200)n(1/2)/(5×1^2)
n=0.3kg(125×300+25200)/(1/2)5×1
n= .3 (37500 +25200)/ 5/2
n= .3 (62700) /2.5
n=7524
so number of strokes required is 7524.
mark it B☺️☺️☺️☺️☺️☺️
L(Heat of fusion)=25200 J/kg
C((Specific heat)=125J/kg ,
∆T(C in temp) =327-27=300K
n(number of strokes) =?
n(1/2)5×1^2=mcΔT+mL
n(1/2)×5×1^2=m(cΔT+L)
=0.3kg(125×300+25200)n(1/2)/(5×1^2)
n=0.3kg(125×300+25200)/(1/2)5×1
n= .3 (37500 +25200)/ 5/2
n= .3 (62700) /2.5
n=7524
so number of strokes required is 7524.
mark it B☺️☺️☺️☺️☺️☺️
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