Question

A 5 kg mass is accelerated from rest to
60 m/s in 1 sec. What force acts on it?
(1) 5 x 60 N
(2) (5/60) 981 N
(3) 602 x 52 N (4) (5/2) * 602 981N​

Answer 1

Answer:

a = 60-0/1=60so force = 5*60

option 1 is correct...

Explanation:

hope it hlps...plz mark it as brainliest and follow me....

Answer 2

Answer:

$\displaystyle F= 5\times60 \ N$

Explanation:

Given :

Mass ( m ) = 5 kg

Initial velocity ( u ) = 0 m / sec

Final  velocity ( v ) = 60 m / sec

Time ( t ) = 1 sec

We have to find Force

We know that

Force = mass × acceleration  ... ( i )

First let us find acceleration

We have  v = u + at

where u = Initial velocity  

v = Final  velocity  

t = time

a = acceleration

put the values in equation we get

60 = 0 + 1 × a

$\displaystyle a=60 \ m/sec^2$

Now put value of a and m in ( i ) we get

$\displaystyle F= 5\times60 \ N$

Thus option 1. is correct.