Question

A 5 kg object is seen in uniform motion which covers 12 m in the direction of its motion in 4 seconds.
The work done on the object during these 4 seconds is​

Answer 1

Answer:

Work done=F.s

and F=ma

m=5kg

s=12m

t=4 sec

so

s=1*a*t^2/2

12=1/2 *a*4*4

24=16a

a=24/16

a=3/2m/s^2

so

Work done=mas

=4*3/2*12

2*3*12

=72 J

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Answer 2

Work done is zero.

Explanation:

Since the motion of the given object is uniform, therefore it has no acceleration and when acceleration is zero we have no force acting on the body hence no work is done.

Uniform motion during the observation,

$\Rightarrow v=constant \Rightarrow a=0$

∵$F=m.a$

∴$F=0$

We know work:

$W=F.s$

$\Rightarrow W=0$

TOPIC: uniform motion, acceleration, force, work

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