Question

. A 5 kg rifle fires a 10 g bullet at velocity of 250 m/s. Calculate its recoil velocity.

Answer 1

hope it'll help u....

Answer 2

Answer

WE KNOW

According to law of conservation of momentum

Final movement= initial movement

so

Let v be the recoil velocity.

Momentum = mass ×velocity

so,

at initially both gun and bullet are at rest

so

P(1)= 0

p(1)=p(2)

=>
$0 = 5v - \frac{10}{1000} \times 250$

$0 = 5v - 40$

$5v = 40$

$v = \frac{40}{5}$

$v = 8m {s}^{ - 1}$