A 5 kg rubber ball is released from a height of 10 m. and is allowed to bounce . After the ball strikes the ground, 10% of the balls kinetic energy is lost in the collision. What is the height of the ball after the height of the ball after the first bounce
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Answer:
Given,
mass of the ball, m=5kg ;
height of the ball, h=10m
Initial potential energy of the ball,
E
p
=mgh=(5)(10)(10)=500J
When the ball reaches the ground, its potential energy becomes zero as it is entirely converted into its kinetic energy (E
k
), i.e.,
E
k
=500J
If v is the velocity attained by the ball just before reaching the ground,
E
k
=
2
1
mv
2
v=
m
2E
k
=
5
2×500
=14.14m/s
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Answer:
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