A 5-kg shark swimming at a speed of 1 m/s swallows an absent-minded 1-kg fish swimming toward it at 4 m/s. The speed of the shark after this meal is
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mass of shark, m1 = 5kg
velocity, v1 = 1 m/s
mass of absent minded fish, m2= 1 kg
velocity, v2 = -4 m/s
(-ve sign comes as the direction of motion is opposite to the direction of motion of shark)
Total mass of shark after swallowing, M = 5+1 = 6kg
let the final velocity of shark = V
According to conservation of momentum,
m1v1 + m2v2 = MV
=> 5×1 + 1×(-4) = 6×V
=> 5 - 4 = 6V
=> 1 = 6V
=> V = 1/6 m/s
Speed of shark after swallowing is 1/6 m/s.
velocity, v1 = 1 m/s
mass of absent minded fish, m2= 1 kg
velocity, v2 = -4 m/s
(-ve sign comes as the direction of motion is opposite to the direction of motion of shark)
Total mass of shark after swallowing, M = 5+1 = 6kg
let the final velocity of shark = V
According to conservation of momentum,
m1v1 + m2v2 = MV
=> 5×1 + 1×(-4) = 6×V
=> 5 - 4 = 6V
=> 1 = 6V
=> V = 1/6 m/s
Speed of shark after swallowing is 1/6 m/s.
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