Question

A 5 kg stone of relative density 3 is resting at
the bed of a lake. It is raised through a height
of 5 m in the lake. If g = 10 m/s2, then work done is

a)500/3 J

b)350/3 J

c)750/3 J

d)550/3 J

plz give correct and good explanation.




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Answer 1

hi dear

your answer is

option A

hopes its helps you

Answer 2

The work done by the stone is 250/3N.

Given:-

Mass of stone = 5kg

Relative density of stone = 3

Height raised = 5m

g = 10m/s²

To Find:-

The work done by the stone.

Solution:-

We can easily calculate the value of work done by the stone by using these simple steps.

As

Mass of stone (m) = 5kg

Relative density of stone (d) = 3

Height raised (h) = 5m

g = 10m/s²

Work done (w) =?

We all know, work done by stone = bouyancy

w = mg×s

According to the formula,

$a = g(1 - \frac{dw}{ds} )$

$a = g \times (1 - \frac{1}{3} )$

$a = - \frac{g}{3}$

here, negative sign represents opposite nature.

Now,

$w = f \times s$

$w = ma \times s$

$w = 5 \times \frac{g}{3} \times 5$

$w = 5 \times \frac{10}{3} \times 5$

$w = \frac{250}{3}$

Hence, The work done by the stone is 250/3N.

#SPJ2