Question

A 5 L cylinder contained 440 g of CO2 gas at 27 degree C. After sometimes it was found that cylinder is empty as all gas has leaked out. If the atmospheric pressure is 1 atm then the work done by the gas is

Answer 1

this is the answer for your questions

Answer 2

Answer: 24443.7J

Explanation: To calculate the moles, we use the formula:

$Moles=\frac{\text {Given mass}}{\text {Molar mass}}$  

$Moles=\frac{440g}{44g/mol}=10mol$  

Initial volume,$V_1= 5L$

Temperature (T) = 27+273 = 300K

Final volume,$V_2=\frac{nRT}{P}=\frac{10\times 0.0821\times 300}{1}=246.3L$

$\Delta V=V_2-V_1=246.30L-5L=241.3L$

Work done by the gas =W=−PΔV=$-1atm\times 241.3L=241.3 Latm$

$=-241.3\times 101.3=-24443.7J$         [1 Latm = 101.3J]