Question

A 5 litre cylinder contains 10 moles of oxygen at 27°c. Due to sudden leakage through the hole, all the gas escapes into the atmosphere and the cylinder got empty. If the atmospheric pressure is 1.0 atmosphere, calculate the work done by the gas.( given R=0.821atmk^-1mol^-1)​

Answer 1

Answer: -2443.7

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Answer 2

$\huge\fbox{Answer ☘}$

$V_{initial} = 5l \\ T = 27°C = 27 + 273K = 300K \\ V_{final} = \frac{nRT}{P} = \frac{10 \times 0.0821 \times 300}{1.0} \\ = > 246.3l \\ \bold\blue{∆V = V_{final} - V_{inital} = 246.3 - 5}\\ \bold\blue{= > 241.3L }\\ \\ \bold{W_{exp} = - P∆V} \\= > - 1 \times 241.3L \: atm \\ = > - 241.3 \times 101.3J \\ = > - 244437 \: J$

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