Question

A 5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall at a point
4 m high. If the foot of the ladder is moved 1.6 m towards the wall, then the distance by which
the top of the ladder would slide upwards on the wall is:
(a) 2 m (b) 1.2 m (c) 0.8 m (d) 0.5 m

Answer 1

Answer: 4.8 cm

STEP  BY STEP EXPLAINATION :

Given:

Hypotneuse = 5 m

Base = ?

altitude = 4 m

Base² = hyp² - alt²

b² = 5² - 4²

b² = 25 - 16

b  = √9

b = 3 m

When base is reduced by 1.6 m

Base = 3 - 1.6 = 1.4 m

hypotneuse =  height of ladder = 5 m

altitude = ?

alt² = hyp²- base²

alt² = 5² - 1.4²

alt² = 25 - 1.96

alt  = √23.04

alt  = 4.8 m

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