Question

A 5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall at point 4 m high. If the foot of the ladder is moved 1.6 towards the wall then find the distance by which the top of the ladder would slide upwards on the wall.​

Answer 1

Answer:

0.8m

Step-by-step explanation:

First, we apply Pythagoras Theorem to find the base,

⇒ H² = P² + B²

⇒ 25 = 16 + B²

⇒ √9 = B

⇒ B = 3m

After the ladder is moved 1.6m towards the wall the base will be,

⇒ Base = 3 - 1.6

⇒ Base = 1.4m

Now again we apply Pythagoras Theorem,

⇒ H² = P² + B²

⇒ 25 = ( 1.4 )² + P²

⇒ √23.04 = P

⇒ P = 4.8m

The length by which ladder moved upwards,

⇒ Ladder moved upwards by = 4.8 - 4 = 0.8m