Question

A 5-m-long ladder when set against the wall of a house reaches a height of 4.8 m. How far is the foot of of the ladder from the wall? ​

Answer 1

Answer:

1.4 m

Step-by-step explanation:

we know that

p²=h²+b²

5²=(4.8)²+b²

or

b²+(4.8)²=5²

b²+ 23.04= 25

b²= 25 - 23.04

b²= 1.96

b=√1.96

b=1.4 m

hope it will helpful to you

Answer 2

Answer:

The ladder is 1.4 m away from the wall.

Given :

• A 5 m long ladder when set against the wall of a house reaches a height of 4.8 m

To find:

• How far is the foot of the ladder from the wall.

Solution:

Let seg AB represent the wall, seg AC represent the ladder and BC represent the distance between wall and the ladder.

=> AB = 4.8 m and AC = 5 m

In triangle ABC, Angle B = 90 °

By pythagoras theorem

AC² = AB² + BC²

=> 5² = 4.8² + BC²

=> BC² = 25 - 23.04

=> BC² = 1.96

On taking square root of both the sides, we get

=> BC = 1.4 m

The ladder is 1.4 m away from the wall.