A 5 m wide cloth is used to make a conical tent of base diameter 14 m and
height 24 m. Find the cost of cloth used at the rate of < 25 per metre
Answers
Answered by
2
First find l
l²=h²+b²
l² = (24)²+(7)²
l² = 576+49
l² = 625
l = 25 m
so curved surface area of conical tent
= π×r ×l
=22×7×25/7
=22×25
=550 m²
1 sq m: 550 sq m :: ₹25: ?₹
=550 × 25
=13750
so total cost of tent 13750 rupees
l²=h²+b²
l² = (24)²+(7)²
l² = 576+49
l² = 625
l = 25 m
so curved surface area of conical tent
= π×r ×l
=22×7×25/7
=22×25
=550 m²
1 sq m: 550 sq m :: ₹25: ?₹
=550 × 25
=13750
so total cost of tent 13750 rupees
Answered by
2
Radius of base (r) and height (h) of the conical tank are 7 m and 24 m
⇒ Slant height (l) = r 2 + h 2
= (7 m) 2 + (24 m) 2
= 49m 2 + 576m 2
= 625m 2
= 25m
Thus,
Curved surface area = πrl = 22 7 × 7 × 25 m 2 = 550m2
⇒ Slant height (l) = r 2 + h 2
= (7 m) 2 + (24 m) 2
= 49m 2 + 576m 2
= 625m 2
= 25m
Thus,
Curved surface area = πrl = 22 7 × 7 × 25 m 2 = 550m2
Now let x m of cloth is rquired
Then C.S.A of conical tank = area of cloth
⇒ 5x = 550
⇒ x = 550 5 = 110
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