A 5 molal solution of sodium carbonate in water having density 1.57g/ml.Find it's molarity.
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Answer:
molarity = 7.831 molar
Explanation:
let the number of moles = n
molality = (number of moles of solute) / weight of solvent in kg
assumption: let the weight of solvent be 1kg
density of solution = 1.57g/ml = 1.57kg/Litre {1g/ml = 1kg/Litre}
so 1 L solution weighs 1.57kg
then volume occupied by 1 kg = 1÷1.57 =0.636L
molality = n/1
5 = n
number of moles = 5
molarity = number of moles / volume
molarity = 5 / 0.636 = 7.831molar
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