Question

A 5 ohm resistor is connected across a battery of 6 volt calculate the current flowing through the resistor and the energy that disappears as heat in 10 seconds

Answer 1

as you know. V = voltage

R =resistance

I = current

V=IR. (ohms law

putting the value

6=5I

I(current) = 1.2 ampere

heat(energy) = I²RT

= 1.2×1.2×5×10

= 72J

I hope it is clear to you

Answer 2

Answer:

1.-1.2 A and 2-72J

Explanation:

1.R=5 ohm , V=6V

I=V/R=6/5=1.2A

2.I=1.2A , t=10s

H=I2RT

H=(1.2)2(5)(10)

H=1.44(50)

H=72J