Question

a 5 ohm resistor is connected across a battery of 6 volts . calculate the current flowing through the resistor and the energy dissipated as heat in 10 second

Answer 1

According to formula

V= R I
SO.

I= V/R
where v voltage, i current ,, R resistance..

SO


I = 6/5
= 1.2 For energy dissipated , Use R= I*V WHERE I= ∆q/∆t ........ 1.2 = ∆q/∆t........ ∆q = 1.2×10. = 12 ..... So, R= ∆q*V/∆t.. 12×6 = 72 using this formula you can easily solve this question Thnk u

Answer 2

Hi there !

Resistance = R = 5Ω

Voltage = V = 6 v

Current = I

I = V/R
  = 6/5
  = 1.2 A

Current flowing through the resistor = 1.2 A

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Heat = H

H = I² × R × t
    = (1.2)² × 5 × 10
    = 72 Joules

energy dissipated as heat in 10 second = 72 J