Question

A 5 ohm resistor is connected across a battery of 6 volts. Calculate(i) The current flowing through the resistor.(ii) The energy that dissipates as heat in 10 s
A) (i) 1.2A (ii) 300J
B) (i) 1.5 A (ii) 500J
C) (i) 2.2A (ii) 300J
D) (i) 2.2A (ii) 500J

Answer 1

Answer:

A 5 ohm resistor is connected across a battery of 6 volts. Calculate(i) The current flowing through the resistor.(ii) The energy that dissipates as heat in 10 s

ANSWER

D) (i) 2.2A (ii) 500J

Answer 2

Given :

• A 5 ohm resistor is connected across a battery of 6 volts.

To Find :

• The current flowing through the resistor.
• The energy that dissipates as heat in 10 s.

Solution :

• Resisiatnce = 5 Ω
• Voltage = 6 V
• Time = 10 seconds
• Current = ?
• Heat = ?

★ Finding the current flowing through the resistor by given below formula :

• I = V/R

[Here, I = current , V = voltage and R = resistance ]

★ Now, subsitute the given values in above formula :

→ I = 6 ÷ 5

→ I = 1.2 A

• Hence,the current flowing through the resistor is 1.2 A.

★ Now, let's calculate the energy that dissipates as heat in 10 s by given below formula :

• H = I² × R × T

[Here,H = heat, I = current , T = time and R = resistance ]

Plug in the given values in above formula :

→ H = (1.2)² × 5 × 10

→ H = 1.44 × 5 × 10

→ H = 1.44 × 50

→ H = 72 J

• Hence,the energy that dissipates as heat in 10 s is 72 J.