Question

A 5 quintal car is moving with a velocity of 54 kmh-1. What is its impulse if it is stopped within 0.5s by application of backward force ? Also determine the force applied.

Answer 1

Mass of the car = 5 quintal
= 500 (1 quintal = 100kg)

Inital velocity (u)= 54km/hr
=(54×1000)/3600
= 15m/s
Final velocity (v) =0
Time taken (t) = 0.5s



Now,

Force= mass × acceleration
= (500) {(0-15)/0.5}
= 500 × -30
= -15000N


Impulse = force × time
=-15000 × 0.5
= -7500 N.s

OR
Impulse = mass (v-u)
= 500 (0-15)
= -7500 N.s

Answer 2

which school do you study in dude

Answer:

Mass of the car = 5 quintal

= 500                                                                                 (1 quintal = 100kg)

u= 54km/hr

=(54×5)/18=3*5

= 15m/s

v=0

Time (t) = 0.5 s

Force= mass × acceleration

= (500) {(0-15)/0.5}

= 500 × -30

= -15000 N

Impulse = force × time

=-15000 × 0.5

= -7500 Ns                      ( si unit of impulse )

(you can also do)

⇒(Impulse = mass (v-u)

= 500 (0-15)

= -7500 Ns)