A 5 quintal car is moving with a velocity of 54kmh-1. what is its impluse if it is stopped within 0.5s by application of bacward force? Also determine the force applied.
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Answer:
Mass of the car = 5 quintal
= 500 (1 quintal = 100kg)
Inital velocity (u)= 54km/hr
=(54×1000)/3600
= 15m/s
Final velocity (v) =0
Time taken (t) = 0.5s
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Now,
Force= mass × acceleration
= (500) {(0-15)/0.5}
= 500 × -30
= -15000N
Impulse = force × time
=-15000 × 0.5
= -7500 N.s
OR
Impulse = mass (v-u)
= 500 (0-15)
= -7500 N.s
Explanation:
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