Physics, asked by neerajsharma36440, 7 months ago

A 5 quintal car is moving with a velocity of 54kmh-1. what is its impluse if it is stopped within 0.5s by application of bacward force? Also determine the force applied.​

Answers

Answered by shreyan4ois
3

Answer:

Mass of the car = 5 quintal

= 500 (1 quintal = 100kg)

Inital velocity (u)= 54km/hr

=(54×1000)/3600

= 15m/s

Final velocity (v) =0

Time taken (t) = 0.5s

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Now,

Force= mass × acceleration

= (500) {(0-15)/0.5}

= 500 × -30

= -15000N

Impulse = force × time

=-15000 × 0.5

= -7500 N.s

OR

Impulse = mass (v-u)

= 500 (0-15)

= -7500 N.s

Explanation:

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