A 5% solution (by mass) of cane sugar in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of pure water is 273.15 K.
NCERT Class XII
Chemistry - Main Course Book I
Chapter 2. Solutions
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There are 50 gms of glucose in water (1kg).
Kf = 1.853 deg K kg/mol
molecular mass of glucose C6 H12 O6 = 180
depression in freezing point: 1.853 * 50/180 = 0.514 deg K
freezing point: 272.635 deg K
Kf = 1.853 deg K kg/mol
molecular mass of glucose C6 H12 O6 = 180
depression in freezing point: 1.853 * 50/180 = 0.514 deg K
freezing point: 272.635 deg K
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