Question

a 5% solution of cane sugar in water has freezing point of 271 k. calculate the freezing ​

Answer 1

Answer:

5% solution (by mass) of cane sugar in water means 5 g of cane sugar is present in (100 - 5)g = 95 g of water. 5% glucose in water means 5 g of glucose is present in (100 - 5) g = 95 g of water. Hence, the freezing point of 5% glucose solution is (273.15 - 4.09) K= 269.06 K.

Explanation:

Hope it help you ✌✌✌