Question

A 5 V battery is connected to two 20 Ω resistors which are joined together in series.
(a) Draw a circuit diagram to represent this. Add an arrow to indicate the direction of conventional current flow in the circuit.
(b) What is the effective resistance of the two resistors?
(c) Calculate the current that flows from the battery?
(d) What is the p.d. across each resistor?

Answer 1

Answer:

The answer is provided in the attachment

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Answer 2

Explanation:

(a) The circuit diagram where a 5 V battery connected to two resistors in series is shown in the below figure.

(b) The effective resistance of the two resistors, $R=R 1+R 2=20 \Omega+20 \Omega=40 \Omega.$

(c) The current that flows from the battery, $I=\frac{v}{R}=\frac{5 V}{40 \mathrm{n}}=0.125 \mathrm{A}.$

(d) The potential difference across each resistor is, $V=I \times R 1=0.125 \times 20=2.5 \mathrm{V}.$