Question

A 5 volt battery is connected to two 20ohm resistors which are joined together in series.
1)draw a circuit diagram to represent this.
2)what is effective resistance of the two resistors?
3)calculate the current that flows from the battery !
4)what is the potential difference across each resistor ?

Answer 1

[2]

» Since two resistors of 20 ohm are connected in series the effective resistance will be :-

=> R = R1 + R2

Here

=> R1 = 20 ohm

=> R2 = 20 ohm

Therefore :-

=> R = 20 + 20

=> R = 40 ohm.

» The effective resistance of the two resistors

=> R = 40 ohm. ______[ANSWER]

_______________________________

[3]

» The current thet flows the battery :-

=> I = V/R = 5/40

=> I = 0.125 A. _______[ANSWER]

________________________________

[4]

» The Potential difference across the 20 ohm resistors :-

=> V = I×R

=> V = 20×0.125 v

=> V = 2.5 v. _________[ANSWER]

» Similarly the potential difference across the 2nd 20 ohm resistor is = 2.5 v

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Answer 2

Answer:

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