Question

A 5 watt source emits monochromatic light of wavelength 5000 Å. When placed 0.5 m away, it liberates photo electrons

Answer 1

The no of electron liberates depends on the intensity of the light. Now the intensity of the light at 0.5 m away is

I0.5=54π×0.52

and the intensity at the 1 m away is

I1=54π×12

So the ratio is

I0.5:I1=54π×0.52:54π×12=4:1

So the number of photoelectrons liberated will be liberated will be reduced by a factor of 4.

Answer 2

Answer:

Check the pic for answer

If u are satisfied mark as brainliest