Question

a^5+x^5÷ a^5-x^5= 122÷121
use properties of proportion to find x

Answer 1

Answer:

here your answer

Step-by-step explanation:

hope it help ☺☺

Answer 2

Answer:

Required value of x is $\frac{a}{3}$

Step-by-step explanation:

Given,

$\frac{ {a}^{5} + {x}^{5} }{ {a}^{5} - {x}^{5} } = \frac{122}{121}$

By componendo and dividendo property of proportion,

$\frac{({a}^{5} + {x}^{5}) + ({a}^{5} - {x}^{5})}{({a}^{5} + {x}^{5}) - ({a}^{5} - {x}^{5})} = \frac{122 + 121}{122 - 121} \\ \frac{{a}^{5} + {x}^{5} +{a}^{5} - {x}^{5} }{{a}^{5} + {x}^{5} - {a}^{5} + {x}^{5}} = \frac{243}{1} \\ \frac{2 {a}^{5} }{2 {x}^{5} } = 243$

$\frac{ {a}^{5} }{ {x}^{5} } = {3}^{5} \\ { (\frac{a}{x}) }^{5} = {3}^{5} \\ \frac{a}{x} = 3 \\ x = \frac{a}{3}$

So, required value of x is

$\frac{a}{3}$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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