A 50.0-kg block is being pulled up a 16.0 (degree) slope by a force of 250 N that is parallel to the slope. The coefficient of kinetic friction between the block and the slope is 0.200. What is the acceleration of the block?
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hay mate here is your answer ....
The gravity force parallel to the slope is 50 kg times sin 13 = 11 .2 kg or 9.8 * 11.2 = 110 N= Normal to to it is 50 kg times cos 13 = 48.7 kg or 477 N. Friction = f*normal force = 477.
250 N is less than 477 * f +110.
f is greater than (250-110)/ 477 is greater than .3
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