Question

a 50.0 kg boy climbs on 100m height calculate the work alone by him​

Answer 1

Answer:

Given,

mass of boy = m = 50 kg

height = h = 100m

since boy does not move anything with his force, work done by him is zero

work done on the boy = gain in potential energy

P.E=mgh

P.E=50×9.8×100

P.E=49KJ

so, potential energy gained by boy is 49 KJ

Answer 2

Given :

• Mass of boy=50kg

• Distance travelled by the boy =100m

To Find :

• The work done alone by him =?

Formula :

$\red \bigstar \boxed{ \bf{force = mass \times acceleration}}$

$\\ \red \bigstar \boxed{ \bf{work \: done = force \times displacement}}$

Solution :

• Mass =50.0kg

• The value of g (acceleration) for earth =9.8 (or approximately 10)

• Displacement =100m

$\\ \implies \sf \: force = mass \times acceleration \\ \\ \implies \sf force = 50.0kg \times 9.8 \\ \\ \implies \sf \: force = 490 \: newton \\ \\ \implies \boxed{ \sf{force = 490 \: newton}}$

$\\ \implies \sf \: work \: done = force \: \times \: displacement \\ \\ \implies \sf \: work \: done = 490 \times 100 \\ \\ \implies \sf \: work \: done \: = 49000 \: joules$

Therefore,

The work done by the boy is 49000 J