Question

A 50.0 ml of impure CaCl2 .2H2O solution sample was
treated with excess AgNO3 solution. The resulting ppt. AgCl
was filtered, washed and dried. It weighed 0.1873 g.
Calculate the % CaCl2.2H2O in solution then express the
conc. of chloride and calcium ions in terms of ppm.
(FW AgCl = 143.32, CaCl2.2H2O= 146.99, Ca = 40.08, Cl =
35.453)​

Answer 1

Answer:

The balanced reaction is as follows:

NaCl+AgNO

3

→AgCl+NaNO

3

143.5 g of AgCl is obtained from 58.5 g of pure NaCl.

0.9 g of AgCl is obtained from

143.5

58.5×0.9

g =0.36 g of pure NaCl.

Percentage purity =

0.5

0.36×100

=72%