A 50 g ball collides elastically with a 150 g ball. The initial velocity of the first ball is 8ms to the left while the second ball is at rest. The velocity of the first ball after collision is?
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mass of each ball=50g=50/1000=0.05kg
initial velocity =16m/s
Initial momentum =P1=m∗u
=16x0.05
=0.8kgm/s
After collision, the direction of velocity of each ball is reversed on rebounding.
Final momentum =P2
=m(−v)
=0.05x(−16)
=−0.8kgm/s
Impulse imparted= Change in momentum of each ball
=−0.8−(0.8)
=−0.16kgm/s
Impulse imparted due to one ball after collision on another would be −0.16kgm/s
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Answer:
We know that Force = Impulse/ Time Impulse = mass * change in velocity
Time = 0.01 s
Mass m = 150 g = 1.5 x 10 ¹kg
Change in velocity = Final - intial velocity = 20 (-12) = 32 m/s
Therefore Force = mass* change in velocity / time = 1.5 x 10 ¹x 32 / 0.01
= 15 x 32 = 480 N
Average force on the ball is 480 N
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