Question

A 50 g mixture of CaCO3 and Na2CO3 heated so that all CaCO3 get converted into CaO and CO2. Volume of CO2 liberate calculated at STP is 5.6 L. Mass of CaO produced is (in gram)

Answer 1

Explanation:

CaCO3= CaO + CO2

total molar mass of CaCO3 and Na2CO3

=(100+106) g = 206g

here the mass of CaCO3 = {(100×50) / 206}

= 24.27184466g

22.4 L CO2 = 56 g CaO

5.6L CO2= {(56×5.6)/22.4}g CaO

= 14 g CaO