A 50 g mixture of CaCO3 and Na2CO3 heated so that all CaCO3 get converted into CaO and CO2. Volume of CO2 liberate calculated at STP is 5.6 L. Mass of CaO produced is (in gram)
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Explanation:
CaCO3= CaO + CO2
total molar mass of CaCO3 and Na2CO3
=(100+106) g = 206g
here the mass of CaCO3 = {(100×50) / 206}
= 24.27184466g
22.4 L CO2 = 56 g CaO
5.6L CO2= {(56×5.6)/22.4}g CaO
= 14 g CaO
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