Question

A 50 gram of bullet is fired a 2 kg pistol with a speed of 1500m/s . What is the speed of recoil of the pistol?

Answer 1

Answer:

-37.5m/s

Explanation:

By the principle of conservation of momentum,

mv= a constant

So, M=0.05 kg

V=1500 m/s

m=2 kg

v=¿

0.05×1500=2×v

So v=37.5 m/s