Question

A 50 grams bullet is Fired from 2kg pistol with a speed of 1500m/s . what is the speed of recoil of pistol
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Answer 1

Answer:

Given the mass of the gun, M = 10 kg,

mass of the bullet, m = 0.05 kg

Speed of the bullet, v = 500 m/s.

Let the velocity of recoil of the gun = V

Using conservation of momentum, we get

Momentum after = momentum before

MV – mv = 0 (as initial momentum was zero)

or, MV = mv

or, 10*V = 500*0.05

or, V = 25/10 = 2.5 m/s

Explanation:

Hope it will help you

Answer 2

(50*10^-3)*(1500)=(2)*(x)

x=37.5

on the principle of conservation of momentum