Physics, asked by alopez0609, 5 months ago

A 50 kg bicyclist on a 10 kg bicycle speeds up from 5.0 m/s to 10 m/s.

Answers

Answered by yashkumar14122001
2

Answer:

375J

Explanation:

Work for changing KE of cyclist+bicycle is

W=Δ KE= KE2 –KE1=

=3000-750 = 2250 J,

for the cyclist:

W1=ΔKE1 = m1•v2^2/2 – m1•v1^2/2 =

=50•100/2-50•25/2 =1875 J,

for the bicycle:

W2=ΔKE2 = m2•v2^2/2 – m2•v1^2/2 =

=10•100/2 - 10•25/2 =375 J

Similar questions