Question

A 50 kg box is pushed with a force 300 N. The box moved with a constant velocity for 5m.
What is the frictional force acting on the box?

Answer 1

Explanation:

$\huge\red{\boxed{\fcolorbox{blue}{orange}{HELLO\:MATE}}}$

Let the frictional force be F.

Now Force acting = 300N

Friction will we acting opposite to the direction of motion

So

$\large\red{\boxed{Net \:force =(300-F)N}}$

Mass of box =50kg

Displacement=5m

Now velocity is constant

So, a =0 (a = acceleration)

$\large\green{\boxed{Force = m× accl^{n}}}$

=(50-F) = 50kg × a

= (50-F)=50×0

50-F =0

so, F =50N

$\purple{\boxed{Frictional\; force = 50N}}$

Therefore frictional force acting of the box is 50N.