A 50 kg boy is in a lift which is moving upwards with acc. of 4m/ s
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ye to koi question nhi hua..... Just an statement.
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The reading on the scale is a measure of the force on the floor by the person. By the Newton's third law this is equal and opposite to the normal force N on the person by the floor.
∴ When the lift is ascending upwards with a acceleration of 9ms
−2
, then
N−50×10=50×9
or $$N=50\times 10+50\times 9=50(10+9)=950N
∴ The reading of weighing machine is 95 kg.
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