Physics, asked by garimamadaan9145, 9 months ago

A 50 kg boy sits 1.2m from the fulcrum of a see saw. Where should another boy of 40 kg sit on
the other side to balance it

Answers

Answered by abhimanyu9667
0

Answer:

at 0.4 m. far from it . hope it helps

Answered by sandipsagare8588
0

Answer:

For a lever,

Load x Load arm = Effort x Effort arm

Here, take the 50 kg boy as the load and the 40 kg boy as the effort.

50 x 1.2 = 40 x effort arm

60 = 40 x effort arm

Effort arm = 1.5 m

So if the 50 kg boy sits 1.2 m from the fulcrum of a see-saw then the other boy of 40 kg should sit on the other side at a distance of 1.5 m from the fulcrum.

Explanation:

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