Question

A 50 kg girl drives horizontally at 2.0m/s in the positive direction from a 200 kg boat initially at rest. What is the recoil velocity of the boat?

Answer 1

Answer:

Before dive both girl and boat are in rest, so total momentum of the system is zero.

When girl dive with velocity V then let say boat will move back in opposite direction with speed v. So new momentum of system will be

MgirlV+mboatv

Form law of conservation of momentum

0 = MgirlV + mboatv

v = −MgirlV / mboat = −50 × 2200 = −0.5 m/s

Negative sign shows that boat moves in direction opposite to girl.

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Answer 2

Explanation:

Answer is given as attachment. ..