Question

A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?
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Answer 1

Explanation:

Mass of the girl, m = 50 kg

Diameter of the heel, d = 1 cm = 0.01 m

Radius of the heel, r = d/2 = 0.005 m

Area of the heel = πr2

= π (0.005)2

= 7.85 × 10–5 m2

Force exerted by the heel on the floor:

F = mg

= 50 × 9.8

= 490 N

Pressure exerted by the heel on the floor:

P = Force / Area

= 490 / (7.85 × 10-5) = 6.24 × 106 Nm-2

Therefore, the pressure exerted by the heel on the horizontal floor is

6.24 × 106 Nm–2.

Answer 2

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Mass of the girl, m = 50 kg

Diameter of the heel, d = 1 cm = 0.01 m

Radius of the heel, r = d/2 = 0.005 m

Area of the heel = πr2

= π (0.005)2

= 7.85 × 10–5 m2

Force exerted by the heel on the floor:

F = mg

= 50 × 9.8

= 490 N

Pressure exerted by the heel on the floor:

P = Force / Area

= 490 / (7.85 × 10-5) = 6.24 × 106 Nm-2

Therefore, the pressure exerted by the heel on the horizontal floor is

6.24 × 106 Nm–2.