A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?
Answers
Answered by
35
Explanation:
Mass of the girl, m = 50 kg
Diameter of the heel, d = 1 cm = 0.01 m
Radius of the heel, r = d/2 = 0.005 m
Area of the heel = πr2
= π (0.005)2
= 7.85 × 10–5 m2
Force exerted by the heel on the floor:
F = mg
= 50 × 9.8
= 490 N
Pressure exerted by the heel on the floor:
P = Force / Area
= 490 / (7.85 × 10-5) = 6.24 × 106 Nm-2
Therefore, the pressure exerted by the heel on the horizontal floor is
6.24 × 106 Nm–2.
Answered by
19
.•♫•HLO dear •♫•.
p = force / area
= mg / π(r/2)^2
= 4mg / πr^2
= 4 × 50 × 9.8 /(22/7)× (10^-2)^2
= 6.2 × 10^6 Pa
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