A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?
Answers
Explanation:
Mass of the girl, m = 50 kg
Diameter of the heel, d = 1 cm = 0.01 m
Radius of the heel, r = d/2 = 0.005 m
Area of the heel = πr2
= π (0.005)2
= 7.85 × 10–5 m2
Force exerted by the heel on the floor:
F = mg
= 50 × 9.8
= 490 N
Pressure exerted by the heel on the floor:
P = Force / Area
= 490 / (7.85 × 10-5) = 6.24 × 106 Nm-2
Therefore, the pressure exerted by the heel on the horizontal floor is
6.24 × 106 Nm–2.
Mass of the girl, m = 50 kg
Diameter of the heel, d = 1 cm = 0.01 m
Radius of the heel, r = d/2 = 0.005 m
Area of the heel = πr^2
= π (0.005)2
= 7.85 × 10–5 m^2
Force exerted by the heel on the floor:
F = mg
= 50 × 9.8
= 490 N
Pressure exerted by the heel on the floor:
P = Force / Area
= 490 / (7.85 × 10-5) = 6.24 × 106 Nm^-2
Therefore, the pressure exerted by the heel on the horizontal floor is
6.24 × 106 Nm^-2