Question

a 50 kg girl wearing high heel shoes balances on a single heel the hill is circular with 1 cm what is the pressure exerted by the hills on the horizontal floor​

Answer 1

Answer:

$6.24 \times {10}^{6} { Nm}^{ - 2}$

Explanation :

Here

m = 50 kg

r = D/2 cm = 1/200m

$pressure = \frac{force}{area } = \frac{mg}{\pi {r}^{2} } \\ \\ \frac{50 \times 9.8}{\frac{22}{7} \times \frac{1}{ {200}^{2} } } = 6.24 \times {10}^{6} {nm}^{2}$

Answer 2

hlo bhai ❤️

pls check the attachment

Hope it helps ❣️

Jai Mahakal ✌️