Question

A 50 kg man standing on the surface of negligible friction kicks forward a 0.1kg stone so that it acquires a speed of 10 ms .T
hen the velocity acquired by the man is

Answer 1

Answer:

Explanation:

       simply conserve momentum , i.e 0.1 x 10 = 50 x v

                                                            v = 0.02 m/s

         hope it helps u...........................................................................................