Question

A 50 kg stone pushed with a force of 60 N rolls on the floor. Its velocity reduces uniformly and gets stopped after 25 seconds. Create a graph which represents the motion of the stone on the floor. Find the acceleration of the stone with the help of your graph.

Answer 1

Answer:

The distance cover by stone is 1125 meters

The Acceleration of stone is 1.2 m/s²

Explanation:

Given as :

The mass of stone = m = 50 kg

The force applied = F = 60 N

Initial velocity = u m/s

Final velocity = v m/s

The time taken to stop the stone = t = 25 seconds

According to question

∵ Force = mass × acceleration

Or F = m × a

Or, 60 N = 50 kg × a

Or, a = $\dfrac{60}{50}$

i.e a = 1.2  N/kg =1.2  m/s²

Acceleration = 1.2 m/s²

Again

v = u + at

Or, a t = v - u

Or, a t = 0 - u

Or, 1.2 m/s² × 25 s= - u

∴  u = - 30 m/s

So, initial velocity = 30 m/s

S = u t + $\dfrac{1}{2}$ a t²

Or, S = 30 × 25 + $\dfrac{1}{2}$ × 1.2 × 25²

Or, S = 750 + 375

Or, S = 1125 m

Hence, The distance cover by stone is 1125 meters

And The Acceleration of stone is 1.2 m/s²     Answer