Question

A 50-litre solution of acid and water contains 10 litres of acid. How much water must be added to make the solution 8% acidic

Answer 1

Equation:

water + water = water

40 + 1.00x = 0.92*(50+x)

Multiply thru by 100 to get:

4000 + 100x = 92*50 + 92x

8x = 600

x = 75 litres (amt. of water to add)

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