Question

A 50 litres solution of acid and water contains 10 litres of acid. How much water must be added to make the solution:8% acidic​

Answer 1

Answer:

75 Litre of water

Step-by-step explanation:

50 litre of solution of acid and water contain

Acid present in the solution = 10 L

Required acid 8% which is = 8/100

Let x amount of water be added to achieve the required %.

In the new solution of acid and water = 10/(50+x)

Therefore,

10/(50+x) = 8/100

10×100 = 8× (50+x)

1000= 400 + 8x

1000 - 400 = 8x

8x = 600

x = 600/8

x=75

Well 75 Litre of water must be added to the solution

Hope its clear for you

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