Question

a 50 micro farad capacitor is charged to 3000v. The energy stored in capacitor is sent through victim during pulse of duration 2ms.the power of pulse is?

Answer 1

The definition of "Capacitance" is the ratio of change in electric charge to the change in electric potential.

Therefore, C = Q/V. Which means that the electric charge, Q = C.V = $50*10^{-6}*3000=0.15$ Coulomb.

Energy stored in the capacitor can be explained as the work done. Since the definition of "Voltage" is the energy stored per unit charge, therefore, E = Q.V = 0.15*3000 = 450 J.

Power is the energy per unit time. Therefore, P = E/t = $\frac{450}{2*10^-3}=225KWatt$